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andioop@programming.dev to Programming Horror@programming.devEnglish ·
edit-2
1 year ago

God I wish there was an easier way to do this

programming.dev

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God I wish there was an easier way to do this

programming.dev

andioop@programming.dev to Programming Horror@programming.devEnglish ·
edit-2
1 year ago
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  • recursive_recursion [they/them]@programming.dev
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    1 year ago

    modulo

    pseudocode:

    if number % 2 == 0
      return "number is even" (is_num_even = 1 or true)
    else
      return "number is odd" (is_num_even = 0 or false)
    

    plus you’d want an input validation beforehand

    • Mac@programming.dev
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      1 year ago

      who needs modulo when you can get less characters out of

      while (number > 1) {
        number -= 2;
      }
      return number;
      

      very efficient

      edit: or theres the trusty iseven api

      • NullPointer@programming.dev
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        1 year ago

        here is somewhat less:

        return (number % 2) == 0;

        • pivot_root@lemmy.world
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          1 year ago

          return !(number & 1);

          • MuchPineapples@lemmy.world
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            1 year ago

            This is the way. Modulo takes too long to compute, bitwise compare should be a lot faster.

            return !(number & 0x1);
            
            • recursive_recursion [they/them]@programming.dev
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              1 year ago

              oh shit yo

              this comment chain is pretty awesome, I learned a lot from this thanks!

        • huf [he/him]@hexbear.net
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          1 year ago

          just check the last bit jesus christ, what is it with these expensive modulo operations?!

          return !(n&1);

      • perviouslyiner@lemm.ee
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        1 year ago

        are the negative numbers all even?

        • I_am_10_squirrels@beehaw.org
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          1 year ago

          Yes

    • avonarret1@programming.dev
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      1 year ago

      🤦

    • Vex_Detrause@lemmy.ca
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      1 year ago
      #You are an input. You have value! You matter!
      if number % 2 == 0
        return "number is even" (is_num_even = 1 or true)
      else
        return "number is odd" (is_num_even = 0 or false)
      

      Am I doing it right? /S.

      • PoolloverNathan@programming.dev
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        1 year ago

        Don’t put nbsps in code blocks, they show up literally.

    • misophist@lemmy.world
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      1 year ago

      Name doesn’t check out.

    • RandomVideos@programming.dev
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      1 year ago

      This code is terrible. If you input 10.66 it returns "number is odd

      It should be:

      if number % 2 == 0
        return "number is even" (is_num_even = 1 or true)
      else
        return "number is not even" (is_num_even = 0 or false)
      
    • comrade_pibb [comrade/them]@hexbear.net
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      1 year ago

      John carmak posting

    • TankieTanuki [he/him]@hexbear.net
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      1 year ago

      are u a wizard?

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